CS502 Midterm Online Quiz

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CS502-Midterm

1 / 50

In Sieve Technique we do not know which item is of interest

2 / 50

After sorting in merge sort algorithm, merging process is invoked.

3 / 50

Due to left complete nature of binary tree, the heap can be stored in

4 / 50

Which may be stable sort:

5 / 50

A heap is a left-complete binary tree that conforms to the ___________

6 / 50

Heaps can be stored in arrays without using any pointers; this is due to the ____________ nature of the binary tree,

7 / 50

Floor and ceiling are ____________ to calculate while analyzing algorithms.

8 / 50

In Heap Sort algorithm, the maximum levels an element can move upward is _________

9 / 50

Random access machine or RAM is a/an

10 / 50

The ancient Roman politicians understood an important principle of good algorithm design that is plan-sweep algorithm.

11 / 50

_______________ is a graphical representation of an algorithm

12 / 50

F (n) and g (n) are asymptotically equivalent. This means that they have essentially the same __________ for large n.

13 / 50

The definition of Theta-notation relies on proving ___________asymptotic bound.

14 / 50

In which order we can sort?

15 / 50

The array to be sorted is not passed as argument to the merge sort algorithm.

16 / 50

If we associate (x, y) integers pair to cars where x is the speed of the car and y is the negation of the price. High y value for a car means a ________ car.

17 / 50

The number of nodes in a complete binary tree of height h is

18 / 50

The time assumed for each basic operation to execute on RAM model of computation is-----

19 / 50

While Sorting, the ordered domain means for any two input elements x and y _________ satisfies only.

20 / 50

Cont sort is suitable to sort the elements in range 1 to k

21 / 50

What is the solution to the recurrence T(n) = T(n/2)+n .

22 / 50

A RAM is an idealized algorithm with takes an infinitely large random-access memory.

23 / 50

_________ is one of the few problems, where provable lower bounds exist on how fast we can sort.

24 / 50

In selection algorithm, because we eliminate a constant fraction of the array with each phase, we get the

25 / 50

The analysis of Selection algorithm shows the total running time is indeed ________in n,

26 / 50

One of the clever aspects of heaps is that they can be stored in arrays without using any _______________.

27 / 50

The function f(n)= n(logn+1)/2 is asymptotically equivalent to n log n. Here Upper Bound means the function f(n) grows asymptotically ____________ faster than n log n.

28 / 50

Upper bound requires that there exist positive constants c2 and n0 such that f(n) ____ c2n for all n <= n0(ye question ghalat lag raha hai mujhae

29 / 50

Asymptotic growth rate of the function is taken over_________ case running time.

30 / 50

For small values of n, any algorithm is fast enough. Running time does become an issue when n gets large.

31 / 50

In 2d-space a point is said to be ________if it is not dominated by any other point in that space.

32 / 50

When we call heapify then at each level the comparison performed takes time

33 / 50

If there are Θ (n2) entries in edit distance matrix then the total running time is

34 / 50

For the Sieve Technique we take time

35 / 50

In ____________ we have to find rank of an element from given input.

36 / 50

Sorting can be in _________

37 / 50

In addition to passing in the array itself to Merge Sort algorithm, we will pass in _________other arguments which are indices.

38 / 50

While solving Selection problem, in Sieve technique we partition input data __________w

39 / 50

For the heap sort we store the tree nodes in

40 / 50

Slow sorting algorithms run in,

41 / 50

In the analysis of Selection algorithm, we eliminate a constant fraction of the array with each phase; we get the convergent _______________ series in the analysis,

42 / 50

The running time of quick sort depends heavily on the selection of

43 / 50

In simple brute-force algorithm, we give no thought to efficiency.

44 / 50

The O-notation is used to state only the asymptotic ________bounds.

45 / 50

In Heap Sort algorithm, the total running time for Heapify procedure is ____________

46 / 50

The sieve technique is a special case, where the number of sub problems is just

47 / 50

The function f(n)=n(logn+1)/2 is asymptotically equivalent to nlog n. Here Lower Bound means function f(n) grows asymptotically at ____________ as fast as nlog n.

48 / 50

We cannot make any significant improvement in the running time which is better than that of brute-force algorithm.

49 / 50

For the worst-case running time analysis, the nested loop structure containing one “for” and one “while” loop, might be expressed as a pair of _________nested summations.

50 / 50

Consider the following code:

For(j=1; j

For(k=1; k<15;k++)

For(l=5; l

{

Do_something_constant();

}

What is the order of execution for this code.

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