CS402 Midterm Online Quiz

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CS402-Midterm

1 / 50

In TG there may exist no paths for certain string.

2 / 50

S = {baa, ab}, then S* will not contain

3 / 50

One FA has n states and m letters in the alphabet. Then FA will have _____ number of transitions in the diagram.

4 / 50

In FA final state represent by _________sign

5 / 50

a (a + b)* is the RE of language defined over S = {a, b} having at least one a

6 / 50

One FA has n states and m letters in the alphabet. Then FA will have _____ number of transitions in the diagram.

7 / 50

The length of output string in case of _________ is one more than the length of corresponding input string.

8 / 50

Then initial state of FA3 will consist of

9 / 50

In which of the following language Rev(s)=s

10 / 50

According to 3rd part of the Kleene’s theorem, If a language can be accepted by an RE then it can be accepted by a _________ as well

11 / 50

If in an NFA, ^ is allowed to be a label of an edge then that NFA is called _________.

12 / 50

In TG there may exist no paths for certain string.

13 / 50

One language can be represented by more than one RE” this statement is____

14 / 50

In GTG’s there may exist no path for a certain string.

15 / 50

In NFA, there may be more than one transition for certain letters and there may not be any transition for certain letters. This statement is ______________.

16 / 50

The clouser FA*(star on an FA ) always accept ______string

17 / 50

FA1 and FA2 are two FA’s representing two languages. Then FA3, which is sum of FA1 and FA2, will accept the strings which are

18 / 50

In FA final state represent by _________sign

19 / 50

a*b* = (ab)* this expression is __________

20 / 50

TG can have more than one initial state.

21 / 50

Alphabet S = {a,bc,cc} has _______ number of letters.

22 / 50

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23 / 50

If r1 and r2 are regular expressions then which of the following is not regular expression.

24 / 50

GTG can have _______________ final state.

25 / 50

If FA1 accepts no string and FA2 accepts many strings, then FA1 + FA2 will be equal to

26 / 50

If L1 and L2 are expressed by regular expressions r1 and r2, respectively then the language expressed by r1 + r2 will be _________

27 / 50

In FA one enter in specific stat but there is no way to leave it then state is called

28 / 50

(a + b)*b is RE for the language defined over S={a,b} having words not ending in a

29 / 50

(a + b)* a is RE for the language defined over S={a,b} having words not ending in b

30 / 50

Languages generated by kleene star are always ______________.

31 / 50

(a+b)*a(a+b)*b(a+b)* is the RE of language defined over S={a,b} having at least one a and one b

32 / 50

In drawing FA3 (which is equal to FA1 + FA2), a state will be declared final if

33 / 50

TG can more then one initial state

34 / 50

GTG can have _______________ final state.

35 / 50

If a language is expressed through TG, then that language will have its RE.

36 / 50

Which of the following is not a word of language EQUAL?

37 / 50

Languages generated by kleene star are always ______________.

38 / 50

FA1 corresponds to r*, then FA1 must accept _______________ string.

39 / 50

If a language can be expressed through FA, then it can also be expressed through TG.

40 / 50

Which statement is true?

41 / 50

Two machines are said to be equivalent if they print the same output string when the different input string is run on them

42 / 50

One language can represents more than one RE.

43 / 50

Using tree structure final state represent by

44 / 50

In TG, there may be a transition for null string.

45 / 50

Alphabet S = {a,bc,cc} has _______ number of letters.

46 / 50

If an alphabet has n number of letter, then number of strings of length m will be

47 / 50

Length of strings, generated by infinite language is_______

48 / 50

S= {a,bc,cc} has the latters

49 / 50

If S = {aa, bb}, then S* will not contain..

50 / 50

If r1 = (aa + bb) and r2 = ( a + b) then the language (aa + bb)* will be generated by

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