CS602-Midterm
1 / 50
A _________ is the set of all points (x , y) that are the same distance from the directrix and focus not on the directrix.
2 / 50
Intensity of the electron beam is controlled by setting __________ levels on the control grid, a metal cylinder that fits over the cathode.
3 / 50
In video text memory, ______ are used to display a character.
4 / 50
In Trivial acceptance/reject test there are four bits of nine regions, Bit 1 represents condition_____.
5 / 50
Which one of the following step is not involved to write pixel using video BIOS services.
6 / 50
The given primitives are clipped to the boundaries of _______ and primitives lying outside are not drawn.
7 / 50
Polygons consisting of ________ can cause problems when rendering.
8 / 50
In Trimetric the direction of projection makes unequal angle with the three principal axes
9 / 50
Concave polygons are a superset of ________ polygons, having fewer restrictions than _____polygons.
10 / 50
Each hyperbola consists of two __________ .
11 / 50
If the value of scaling factors sx and sy is greater than 1, then size of objects will be ____________.
12 / 50
25 * 10 resolution with 16 colors supports
13 / 50
We can draw the circle
14 / 50
_________ direct view storage tube maintains the picture display.
15 / 50
A scaling transformation alters the ______ of an object.
16 / 50
Intensity of the electron beam is controlled by setting _________ levels on the control grid, a metal cylinder that fits over the cathode.
17 / 50
Parity is a concept used to determine which ________ lie within a polygon.
18 / 50
We can draw the circle using ___________.
19 / 50
The basis functions fi(u) in Bezier curve must be symmetric with respect to u and (u-2)
20 / 50
Orthographic projections that show more than one side of an object are called __________ projections.
21 / 50
Cross product of two vectors result in a ___________.
22 / 50
Vectors can be multiplied in a way
23 / 50
Polygons are basically concave polygons that may have self-intersecting edges
24 / 50
There are _________ basic types of polygon.
25 / 50
__________ projection is obtained by projecting points along parallel lines that are not perpendicular to the projection plane.
26 / 50
Three or more points that lie on the same line are called _____.
27 / 50
Global coordinate systems can be defined with respect to local coordinate system
28 / 50
Shortcoming of Sutherland-Hodgeman Algorithm is concave polygons may be displayed with extensors lines
29 / 50
We can take transpose of any matrix.
30 / 50
Tessellation can be adaptive to the ____________ degree of curvature of a surface.
31 / 50
Because clipping against one edge is independent to all others, so it is ________ arrange the clipping stages in a pipeline.
32 / 50
In 2D transformation, ______ can be achieved by rotating the object about 110 degrees.
33 / 50
We can take transpose of __________.
34 / 50
DDA abbreviated for ________.
35 / 50
Rotating a point requires
36 / 50
Various curve functions are useful in ______.
37 / 50
To move a _________ from one location to another, we translate the center point and redraw the same using new center point.
38 / 50
Both Boundary Filling and Flood filling algorithms are non-recursive techniques.
39 / 50
Discard a line with both endpoints outside clipping boundaries is called as
40 / 50
41 / 50
When scaling factor Sx and Sy are assigned the same value, __________ scaling is produced that maintains relative object proportions.
42 / 50
Perspective projection is specified with the function glFrustum().
43 / 50
Monochrome Adapter (MA) is a single color adapter
44 / 50
The curve is always contained within the _______ of the control points
45 / 50
Because clipping against one edge is independent of all others, so it is _______ to arrange the clipping stages in a pipeline.
46 / 50
47 / 50
UV light is used in Plasma Panel displays to excite phosphor.
48 / 50
A two dimensional rotation is applied to an object by repositioning it along a _____ path in the XY plane
49 / 50
The process of subdivision an entity or surface into one or more non-overlapping primitives.
50 / 50
A * B = |A| * |B| * cos(?) where ? is the angle between the two vectors
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