CS604-Midterm
1 / 50
The condition where a set of blocked processes each holding a resource and waiting to acquire a resource held by another process in the set, is termed as ________.
2 / 50
A_____ is an abstract key for accessing a file.
3 / 50
A semaphore that cause Busy-Waiting is termed as .
4 / 50
You can display all of the signals supported by your system, along with their numbers, by using the -----------command
5 / 50
A solution to the critical section problem must satisfy the following requirements
6 / 50
Hardware provide basic computing resource.
7 / 50
The critical section problem can be solved by the following except
8 / 50
If the system can allocate resources to each process in some order and still avoid a deadlock then it said to be in ______ state.
9 / 50
Which of the following is NOT a Hardware Resource.
10 / 50
The priorities of processes in the __________ group remain fixed.
11 / 50
In Resource Allocation Graph, A _______ Pi →Rj indicates that process Pi may request resource Rj at some time in the future.
12 / 50
Batch programs are usually _________ programs.
13 / 50
Kernel is responsible for scheduling the user level threads.
14 / 50
All threads within a process share the ________ address space.
15 / 50
An absolute pathname starts with the root directory (/) and a relative pathname starts with your home directory.
16 / 50
Round Robin algorithm is similar to ____________ scheduling but preemption is added to switch between processes.
17 / 50
A parent process calling __________ system call will be suspended until children process terminates.
18 / 50
___________ is a solution to the problem of indefinite blockage of low-priority processes.
19 / 50
A Process „A‟ that has finished working but its parent process has also finished its execution. In this state the process „A‟ will be called as _____ process.
20 / 50
-------- command gives a snapshot of the current processes.
21 / 50
Which register holds the smallest legal physical memory address for a process?
22 / 50
We can install and run multiple OS by using VMWare.
23 / 50
Linux Treats Devices as Files.
24 / 50
You can use the ------------- command to display the status of suspended and background processes
25 / 50
Which part of the computer system helps in managing the file and memory management system?
26 / 50
I/O instructions are Privileged Instructions.
27 / 50
You can use the rm file1 command to __________ file1
28 / 50
Operating System provides services such as Managing Primary and Secondary Storage, Processes and Allowing user to manage his/her files and directories.
29 / 50
In Layered approach of OS, Lowest Layer is known as ________.
30 / 50
The bottom-up view is that operating system is a resource manager who manages the hardware and software resources in the computer system.
31 / 50
____ command display the status of a process.
32 / 50
n-process critical section problem can be solved by using
33 / 50
In ________addressing, the recipient is not required to name the sender.
34 / 50
The returned code to the child process after successful fork system call execution is
35 / 50
The bottom layer in the layered approach of Operating System is-----------
36 / 50
The main characteristic of a Real time system is
37 / 50
An operating system is a control program that manages the execution of user programs to prevent errors and improper use of a computer.
38 / 50
___________ is a piece of code in a cooperating process in which the process may updates shared data (variable, file, database, etc.).
39 / 50
Shared libraries and kernel modules are stored in directory
40 / 50
Operating System is the Manager of Hardware Resources.
41 / 50
The scheduling of ______ are done by the operating system.
42 / 50
In indirect inter process communication, a sender ________ mention the name of the recipient.
43 / 50
44 / 50
____ command gives a snapshot of the current processes.
45 / 50
A_______ is an integer variable that, apart from initialization is accessible only through two standard atomic operations: wait and signal.
46 / 50
copy file1 file2 is an example of ______ OS view.
47 / 50
The performance of Round Robin algorithm does NOT depends heavily on the size of the time quantum.
48 / 50
The manual pages can be read in Linux using ____ command.
49 / 50
The major advantage of multi-programming system is
50 / 50
__________ commands in Linux is used to copy file
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