CS604-Midterm
1 / 50
In ---------addressing; the recipient is not required to name the sender.
2 / 50
Managing Secondary Storage Involves all of the Following except
3 / 50
A semaphore that cause Busy-Waiting is termed as ___________.
4 / 50
A major problem with priority scheduling algorithms is ______.
5 / 50
________ scheduling algorithm is sometimes called shortest remaining time first scheduling algorithm.
6 / 50
A semaphore that cause Busy-Waiting is termed as .
7 / 50
In deadlock detection and recovery algorithm, a deadlock exists in the system if and only if the wait for graph contains a _____________
8 / 50
________ determines What will be done.
9 / 50
Linux uses ___________ directory to store system configuration files.
10 / 50
Which of the following is correct definition for wait operation?
11 / 50
Kernel is responsible for scheduling the user level threads.
12 / 50
You can use the ------------- command to display the status of suspended and background processes
13 / 50
_____ system call is used to write to a file or FIFO or any other IPC channel.
14 / 50
The execution of critical sections must NOT be mutually exclusive
15 / 50
The number of processes completed per unit time is called ___________.
16 / 50
The process of switching from one process to another is called ---------------.
17 / 50
n-process critical section problem can be solved by using
18 / 50
When a process opens its first file explicitly it will get descriptor number _________
19 / 50
Operating System provides services such as Managing Primary and Secondary Storage, Processes and Allowing user to manage his/her files and directories.
20 / 50
Round Robin algorithm is similar to ____________ scheduling but preemption is added to switch between processes.
21 / 50
Banker‟s algorithm is used for ________________
22 / 50
The ________ requires that once a writer is ready, that writer performs its write as soon as possible , if a writer waiting to access the object, no new readers may start reading.
23 / 50
A solution to the critical section problem must satisfy the following requirements
24 / 50
The basic purpose of ________________is to help the users to utilize the hardware resources for completing different tasks in a simplified manner
25 / 50
Time interval when the I/O Devices are accessed is known as --------.
26 / 50
Swapper is also termed as Short term scheduler.
27 / 50
Command-line interpreter is also called __________ in some operating systems.
28 / 50
The correct command for compiling C program named program.c in Linux environment is
29 / 50
Preventing a condition of ________ to happen, deadlocks can be prevented to happen.
30 / 50
Operating System is the Manager of Hardware Resources.
31 / 50
The creating process is called a--------------- process while the new processes are called the -------------- of that process
32 / 50
If a system is not in a safe state, there can be No deadlocks.
33 / 50
Starvation is infinite blocking caused due to unavailability of resources.
34 / 50
A time sharing system is
35 / 50
Linux is a version of _______ operating system.
36 / 50
First-Come, First-Served (FCFS) is a --------------scheduling algorithm.
37 / 50
Current working directory can be accessed using --------- Command.
38 / 50
-------- command gives a snapshot of the current processes.
39 / 50
Hardware provide basic computing resource.
40 / 50
The major advantage of multi-programming system is
41 / 50
In Layered approach of OS, Lowest Layer is known as ________.
42 / 50
A process is said to be in critical section if it executes code that manipulates shared data
43 / 50
Which of the following is NOT a Hardware Resource.
44 / 50
Shared libraries and kernel modules are stored in directory
45 / 50
_________________ scheduling allows a process to move between queues.
46 / 50
Which part of the computer system helps in managing the file and memory management system?
47 / 50
The returned code to the child process after successful fork system call execution is
48 / 50
__________ scheduler selects the process from the job pool and put them in main memory.
49 / 50
The bottom layer in the layered approach of Operating System is-----------
50 / 50
DOS is single user operating system.
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